GeoSeries.overlaps

Returns True for all aligned geometries that overlap other, else False. In the original Geopandas, Geometries overlap if they have more than one but not all points in common, have the same dimension, and the intersection of the interiors of the geometries has the same dimension as the geometries themselves. However, in Sedona, we return True in the case where the geometries points match. Note: Sedona’s behavior may also differ from Geopandas for GeometryCollections. The operation works on a 1-to-1 row-wise manner.

Signature

overlaps(other, align=None) -> pspd.Series

Parameters

GeoSeries or geometric object

required

The GeoSeries (elementwise) or geometric object to test if overlaps.

bool | None (default None)

default:"None"

If True, automatically aligns GeoSeries based on their indices. None defaults to True. If False, the order of elements is preserved.

Returns

Series(bool)

This method works in a row-wise manner. It does not check if an element of one GeoSeries overlaps any element of the other one.

See also

GeoSeries.crosses
GeoSeries.intersects

Examples

>>> from sedona.spark.geopandas import GeoSeries
>>> from shapely.geometry import Polygon, LineString, MultiPoint, Point
>>> s = GeoSeries(
...     [
...         Polygon([(0, 0), (2, 2), (0, 2)]),
...         Polygon([(0, 0), (2, 2), (0, 2)]),
...         LineString([(0, 0), (2, 2)]),
...         MultiPoint([(0, 0), (0, 1)]),
...     ],
... )
>>> s2 = GeoSeries(
...     [
...         Polygon([(0, 0), (2, 0), (0, 2)]),
...         LineString([(0, 1), (1, 1)]),
...         LineString([(1, 1), (3, 3)]),
...         Point(0, 1),
...     ],
... )

We can check if each geometry of GeoSeries overlaps a single geometry:

>>> polygon = Polygon([(0, 0), (1, 0), (1, 1), (0, 1)])
>>> s.overlaps(polygon)
0     True
1     True
2    False
3    False
dtype: bool

We can also check two GeoSeries against each other, row by row. The GeoSeries above have different indices. We align both GeoSeries based on index values and compare elements with the same index.

>>> s.overlaps(s2)
  False
   True
  False
  False
  False
dtype: bool

>>> s.overlaps(s2, align=False)
0     True
1    False
2     True
3    False
dtype: bool

​Signature

​Parameters

​Returns

​Examples

Signature

Parameters

Returns

Examples